What is the domain of f(x)=sqrt((x+1)(x+1-1)(x+1-2)) ?

The domain of f(x)=sqrt((x+1)(x+1-1)(x+1-2)) is -1 = 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x+1)(x+1-1)(x+1-2))

domain

f (x) = (x + 1) (x + 1 - 1) (x + 1 - 2)

- 1 \leq x \leq 0 or x \geq 1

Interval Notation

[- 1, 0] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 0 or x \geq 1

The function domain

- 1 \leq x \leq 0 or x \geq 1

y^{3} + 3 x = 6

\frac{x ^{2} - 1}{5 x ^{2} + 5 x}

f (x) = \frac{x ^{2}}{x ^{2} - x - 6}

\frac{x ^{2} - 4 x - 8}{[ - 3.6 ]}

\frac{- 8 x + 9}{1 + x}

What is the domain of f(x)=sqrt((x+1)(x+1-1)(x+1-2)) ?
The domain of f(x)=sqrt((x+1)(x+1-1)(x+1-2)) is -1<= x<= 0\lor x>= 1