What is the domain of f(x)=(x^2-1)^{1/2} ?

The domain of f(x)=(x^2-1)^{1/2} is x = 1

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domain of f(x)=(x^2-1)^{1/2}

domain

f (x) = (x^{2} - 1)^{\frac{1}{2}}

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

f (x) = \frac{10}{2 - 3 x}

y = (x + 1)

f (x) = lo g_{\frac{1}{3}} (x^{2} + x + 1)

f (x) = arccos (x - 1) sec (x)

\frac{1}{2 x 9 + ln ( x )}

What is the domain of f(x)=(x^2-1)^{1/2} ?
The domain of f(x)=(x^2-1)^{1/2} is x<=-1\lor x>= 1