What is the domain of (x^3-6x^2+4x+8)/(x^3-x^2-9x+9) ?

The domain of (x^3-6x^2+4x+8)/(x^3-x^2-9x+9) is x 3

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domain of (x^3-6x^2+4x+8)/(x^3-x^2-9x+9)

domain

\frac{x ^{3} - 6 x ^{2} + 4 x + 8}{x ^{3} - x ^{2} - 9 x + 9}

x < - 3 or - 3 < x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3, x = 3

The function domain

x < - 3 or - 3 < x < 1 or 1 < x < 3 or x > 3

y = \frac{x ^{2} - x}{x ^{2} - 1}

f (x) = \frac{3 x + 2}{x + 4}

f (x) = lo g_{10} (5) (3 x^{2} - 5 x + 2)

f (x) = \frac{1}{( x ^{2} - x )}

f (x) = \frac{x - 1}{x + 1}

What is the domain of (x^3-6x^2+4x+8)/(x^3-x^2-9x+9) ?
The domain of (x^3-6x^2+4x+8)/(x^3-x^2-9x+9) is x<-3\lor-3<x<1\lor 1<x<3\lor x>3