What is the domain of f(x)=sqrt((x-2)(x^2+3x)) ?

The domain of f(x)=sqrt((x-2)(x^2+3x)) is -3 = 2

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domain of f(x)=sqrt((x-2)(x^2+3x))

domain

f (x) = (x - 2) (x^{2} + 3 x)

- 3 \leq x \leq 0 or x \geq 2

Interval Notation

[- 3, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 0 or x \geq 2

The function domain

- 3 \leq x \leq 0 or x \geq 2

f (x) = \frac{4 x - 2 x ^{2}}{x - 2}

f (x) = lo g_{10} (\frac{x ^{2} - 9}{x - 3})

\frac{1}{3} x - 3

g (x) = \frac{x + 8}{x ^{2} - 16 + 64}

f (x) = \frac{x}{x ^{2} - x - 6}

What is the domain of f(x)=sqrt((x-2)(x^2+3x)) ?
The domain of f(x)=sqrt((x-2)(x^2+3x)) is -3<= x<= 0\lor x>= 2