What is the domain of f(x)=((e^x-1))/((e^x-2)) ?

The domain of f(x)=((e^x-1))/((e^x-2)) is x ln(2)

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domain of f(x)=((e^x-1))/((e^x-2))

domain

f (x) = \frac{( e ^{x} - 1 )}{( e ^{x} - 2 )}

x < ln (2) or x > ln (2)

Interval Notation

(- \infty, ln (2)) \cup (ln (2), \infty)

Solution steps

Find undefined (singularity) points:

x = ln (2)

The function domain

x < ln (2) or x > ln (2)

\frac{ln ( x ) sinh ( x )}{x}

f (x) = lo g_{2} (1 - x^{2})

f (x) = \frac{1}{x ^{2} + x - 6} + - x + 1

f (x) = ln (x^{2} + 64)

\frac{3 x}{8 x - 1}

What is the domain of f(x)=((e^x-1))/((e^x-2)) ?
The domain of f(x)=((e^x-1))/((e^x-2)) is x<ln(2)\lor x>ln(2)