What is the domain of sqrt(x^2+2x-3) ?

The domain of sqrt(x^2+2x-3) is x = 1

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domain of sqrt(x^2+2x-3)

domain

x^{2} + 2 x - 3

x \leq - 3 or x \geq 1

Interval Notation

(- \infty, - 3] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 1

The function domain

x \leq - 3 or x \geq 1

f (x) = \frac{2 x ^{2} - 4}{3 x ^{2} + 6 x - 45}

f (x) = 2 + x^{3} - 2 x^{2} - x + 2

f (x) = \frac{70}{x}

f (x) = ln (0.5 + y)

4 [x + 2]

What is the domain of sqrt(x^2+2x-3) ?
The domain of sqrt(x^2+2x-3) is x<=-3\lor x>= 1