What is the domain of f(x)=(x+3)/(2x-7) ?

The domain of f(x)=(x+3)/(2x-7) is x 7/2

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domain of f(x)=(x+3)/(2x-7)

domain

f (x) = \frac{x + 3}{2 x - 7}

x < \frac{7}{2} or x > \frac{7}{2}

Interval Notation

(- \infty, \frac{7}{2}) \cup (\frac{7}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{2}

The function domain

x < \frac{7}{2} or x > \frac{7}{2}

\frac{1}{2 x ^{2} + x - 6}

36 x + 49

f (x) = (4 x^{3} - 48 x^{2} + 144 x)

f (x) = \frac{( x + 7 )}{x ^{2} - 49}

f (x) = \frac{17}{( 1 - 4 x ) ^{2}}

What is the domain of f(x)=(x+3)/(2x-7) ?
The domain of f(x)=(x+3)/(2x-7) is x< 7/2 \lor x> 7/2