What is the domain of f(x)=log_{x}(4-x^2) ?

The domain of f(x)=log_{x}(4-x^2) is 0<x<1\lor 1<x<2

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domain of f(x)=log_{x}(4-x^2)

domain

f (x) = lo g_{x} (4 - x^{2})

0 < x < 1 or 1 < x < 2

Interval Notation

(0, 1) \cup (1, 2)

Solution steps

Check logs domain:

0 < x < 1 or 1 < x < 2

The function domain

0 < x < 1 or 1 < x < 2

f (x) = lo g_{2} (x^{2} + 64)

y = \frac{- 3}{5 x + 20} + 7

f (x) = 1 - (x - 1)^{2}

f (x) = \frac{- 1}{x - 1}

f (x) = ln (x) - e^{x} - x

What is the domain of f(x)=log_{x}(4-x^2) ?
The domain of f(x)=log_{x}(4-x^2) is 0<x<1\lor 1<x<2