What is the domain of f(x)=(sqrt(x+8))/(2x+4) ?

The domain of f(x)=(sqrt(x+8))/(2x+4) is -8 -2

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domain of f(x)=(sqrt(x+8))/(2x+4)

domain

f (x) = \frac{x + 8}{2 x + 4}

- 8 \leq x < - 2 or x > - 2

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

- 8 \leq x < - 2 or x > - 2

f (x) = - 5 x - 10 + 6

v (x) = 9 - x

f (x) = ln (e^{∣ x^{2} + 2 x + 1 ∣} - e)

h (x) = \frac{x ^{2} - 4}{2}

f (x) = \frac{4 x}{x ^{2} + 1}

What is the domain of f(x)=(sqrt(x+8))/(2x+4) ?
The domain of f(x)=(sqrt(x+8))/(2x+4) is -8<= x<-2\lor x>-2