What is the domain of f(x)=((sqrt(-5t)+34))/(40-4t) ?

The domain of f(x)=((sqrt(-5t)+34))/(40-4t) is t<= 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((sqrt(-5t)+34))/(40-4t)

domain

f (x) = \frac{( - 5 t + 34 )}{40 - 4 t}

t \leq 0

Interval Notation

Solution steps

Find non-negative values for radicals:

t \leq 0

Find undefined (singularity) points:

t = 10

Combine real regions and undefined points for final function domain

t \leq 0

(x^{2} + 2)

f (y) = 3 \frac{y}{y - 4}

f (x) = \frac{x ( x - 1 )}{x - 1}

y = \frac{cos ( t )}{ln ∣ t + 1 ∣}

f (x) = h (x, t) = - 0.0625 t^{2} + 3 t - 20

What is the domain of f(x)=((sqrt(-5t)+34))/(40-4t) ?
The domain of f(x)=((sqrt(-5t)+34))/(40-4t) is t<= 0