What is the domain of y=log_{2}(sqrt(4-x^2)) ?

The domain of y=log_{2}(sqrt(4-x^2)) is -2<x<2

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domain of y=log_{2}(sqrt(4-x^2))

domain

y = lo g_{2} (4 - x^{2})

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

Find positive values for logs:

- 2 < x < 2

The function domain

- 2 < x < 2

f (x) = \frac{3 x - 7}{5 x + 6}

\frac{x ^{2} - 8 x + 16}{3 x - 12}

f (x) = \frac{x - 3}{x ^{2} - 4 x - 32}

(x^{2} + 2 x - 1) (2 x^{2} - 3 x + 6)

f (x) = 2 x^{2} - 300 x + 10528

What is the domain of y=log_{2}(sqrt(4-x^2)) ?
The domain of y=log_{2}(sqrt(4-x^2)) is -2<x<2