What is the domain of f(x)=(x-3)/(x^2-4x-32) ?

The domain of f(x)=(x-3)/(x^2-4x-32) is x 8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-3)/(x^2-4x-32)

domain

f (x) = \frac{x - 3}{x ^{2} - 4 x - 32}

x < - 4 or - 4 < x < 8 or x > 8

Interval Notation

(- \infty, - 4) \cup (- 4, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 4

The function domain

x < - 4 or - 4 < x < 8 or x > 8

(x^{2} + 2 x - 1) (2 x^{2} - 3 x + 6)

f (x) = 2 x^{2} - 300 x + 10528

arctan (\frac{x}{2})

f (x) = \frac{1 + x}{2 x - x ^{2}}

f (x) = ln (x^{3} + 3 x^{2} + 3 x + 1)

What is the domain of f(x)=(x-3)/(x^2-4x-32) ?
The domain of f(x)=(x-3)/(x^2-4x-32) is x<-4\lor-4<x<8\lor x>8