What is the domain of (x^2-8x+16)/(3x-12) ?

The domain of (x^2-8x+16)/(3x-12) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2-8x+16)/(3x-12)

domain

\frac{x ^{2} - 8 x + 16}{3 x - 12}

x < 4 or x > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4

The function domain

x < 4 or x > 4

f (x) = \frac{x - 3}{x ^{2} - 4 x - 32}

(x^{2} + 2 x - 1) (2 x^{2} - 3 x + 6)

f (x) = 2 x^{2} - 300 x + 10528

arctan (\frac{x}{2})

f (x) = \frac{1 + x}{2 x - x ^{2}}

What is the domain of (x^2-8x+16)/(3x-12) ?
The domain of (x^2-8x+16)/(3x-12) is x<4\lor x>4