What is the domain of f(x)=(1+x)/(sqrt(2x-x^2)) ?

The domain of f(x)=(1+x)/(sqrt(2x-x^2)) is 0<x<2

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domain of f(x)=(1+x)/(sqrt(2x-x^2))

domain

f (x) = \frac{1 + x}{2 x - x ^{2}}

0 < x < 2

Interval Notation

(0, 2)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

Find undefined (singularity) points:

x = 0, x = 2

Combine real regions and undefined points for final function domain

0 < x < 2

f (x) = ln (x^{3} + 3 x^{2} + 3 x + 1)

y = \frac{2 x}{x ^{2} - 1}

f (x) = (1 + \frac{1}{x})^{2}

f (x) = x + \frac{256}{x ^{2}}

f (x) = - 9 - x

What is the domain of f(x)=(1+x)/(sqrt(2x-x^2)) ?
The domain of f(x)=(1+x)/(sqrt(2x-x^2)) is 0<x<2