What is the domain of f(x)= 1/(sqrt(4-\sqrt{2-x))} ?

The domain of f(x)= 1/(sqrt(4-\sqrt{2-x))} is -14<x<= 2

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domain of f(x)= 1/(sqrt(4-\sqrt{2-x))}

domain

f (x) = \frac{1}{4 - 2 - x}

- 14 < x \leq 2

Interval Notation

(- 14, 2]

Solution steps

Find non-negative values for radicals:

- 14 \leq x \leq 2

Find undefined (singularity) points:

x = - 14

Combine real regions and undefined points for final function domain

- 14 < x \leq 2

f (x) = - x^{2} - 3 x + 4

f (x) = \frac{x - 1}{x ^{2} + 6 x - 27}

y = \frac{x + 1}{2 x + 1}

f (x) = ∣ x ∣ - x

\frac{x ^{2}}{6 - x}

What is the domain of f(x)= 1/(sqrt(4-\sqrt{2-x))} ?
The domain of f(x)= 1/(sqrt(4-\sqrt{2-x))} is -14<x<= 2