What is the domain of f(x)=-sqrt(1/2 x^2+2x) ?

The domain of f(x)=-sqrt(1/2 x^2+2x) is x = 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=-sqrt(1/2 x^2+2x)

domain

f (x) = - \frac{1}{2} x^{2} + 2 x

x \leq - 4 or x \geq 0

Interval Notation

(- \infty, - 4] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 0

The function domain

x \leq - 4 or x \geq 0

f (x) = \frac{2 x - 1}{2 x + 1}

f (x) = \frac{x - 9}{x - 2}

f (t) = \frac{1}{t}

What is the domain of f(x)=-sqrt(1/2 x^2+2x) ?
The domain of f(x)=-sqrt(1/2 x^2+2x) is x<=-4\lor x>= 0