What is the domain of f(x)=sqrt(8+2x-x^2) ?

The domain of f(x)=sqrt(8+2x-x^2) is -2<= x<= 4

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domain of f(x)=sqrt(8+2x-x^2)

domain

f (x) = 8 + 2 x - x^{2}

- 2 \leq x \leq 4

Interval Notation

[- 2, 4]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 4

The function domain

- 2 \leq x \leq 4

- 2^{x} + 3

f (x) = \frac{x + 4}{3 x + 9}

f (x) = 5^{x - 2}

\frac{6 x - 1}{( x - 3 ) ( x + 1 )}

y = \frac{x - 4}{x - 2}

What is the domain of f(x)=sqrt(8+2x-x^2) ?
The domain of f(x)=sqrt(8+2x-x^2) is -2<= x<= 4