What is the domain of f(x)=(sqrt(x+4))/(3x+9) ?

The domain of f(x)=(sqrt(x+4))/(3x+9) is -4 -3

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domain of f(x)=(sqrt(x+4))/(3x+9)

domain

f (x) = \frac{x + 4}{3 x + 9}

- 4 \leq x < - 3 or x > - 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

- 4 \leq x < - 3 or x > - 3

f (x) = 5^{x - 2}

\frac{6 x - 1}{( x - 3 ) ( x + 1 )}

y = \frac{x - 4}{x - 2}

x^{2} + 4 x

h (x) = \frac{x ^{2} - 4}{2}

What is the domain of f(x)=(sqrt(x+4))/(3x+9) ?
The domain of f(x)=(sqrt(x+4))/(3x+9) is -4<= x<-3\lor x>-3