What is the domain of (6x-1)/((x-3)(x+1)) ?

The domain of (6x-1)/((x-3)(x+1)) is x 3

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domain of (6x-1)/((x-3)(x+1))

domain

\frac{6 x - 1}{( x - 3 ) ( x + 1 )}

x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 1

The function domain

x < - 1 or - 1 < x < 3 or x > 3

y = \frac{x - 4}{x - 2}

x^{2} + 4 x

h (x) = \frac{x ^{2} - 4}{2}

∣ 2 x ∣

f (x) = 7 x - 9

What is the domain of (6x-1)/((x-3)(x+1)) ?
The domain of (6x-1)/((x-3)(x+1)) is x<-1\lor-1<x<3\lor x>3