What is the domain of 3/(sqrt(x-2)) ?

The domain of 3/(sqrt(x-2)) is x>2

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domain of 3/(sqrt(x-2))

domain

\frac{3}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = - x + sin (x)

f (x) = x^{3} - 10

\frac{( - x - 3 )}{( 2 - x )}

5 (9 - x^{2})

y = \frac{6 - t}{t ^{2} - t - 2}