What is the domain of f(x)=sqrt(3-2x)+1 ?

The domain of f(x)=sqrt(3-2x)+1 is x<= 3/2

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domain of f(x)=sqrt(3-2x)+1

domain

f (x) = 3 - 2 x + 1

x \leq \frac{3}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2}

The function domain

x \leq \frac{3}{2}

72 - x^{2} + x

2 - 3 X

f (x) = 5 - x + 3 x - 1

f (x) = ln (\frac{1}{x - 6})

y = 2 x + 3

What is the domain of f(x)=sqrt(3-2x)+1 ?
The domain of f(x)=sqrt(3-2x)+1 is x<= 3/2