What is the domain of (x^2+5x-14)/((x+1)(x-3)(x+7)) ?

The domain of (x^2+5x-14)/((x+1)(x-3)(x+7)) is x 3

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domain of (x^2+5x-14)/((x+1)(x-3)(x+7))

domain

\frac{x ^{2} + 5 x - 14}{( x + 1 ) ( x - 3 ) ( x + 7 )}

x < - 7 or - 7 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 7) \cup (- 7, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3, x = - 7

The function domain

x < - 7 or - 7 < x < - 1 or - 1 < x < 3 or x > 3

\frac{1 0 ^{3 x}}{2}

f (x) = ∣ y - x ∣ = [x]

f (x) = \frac{10}{9 - x ^{2}}

f (x) = \frac{x + 3}{x ^{2} + 9 x + 18}

f (x) = 2 x^{2} + 8 x - 5

What is the domain of (x^2+5x-14)/((x+1)(x-3)(x+7)) ?
The domain of (x^2+5x-14)/((x+1)(x-3)(x+7)) is x<-7\lor-7<x<-1\lor-1<x<3\lor x>3