What is the domain of f(x)=(sqrt(x+3)}{\frac{x+4)/2} ?

The domain of f(x)=(sqrt(x+3)}{\frac{x+4)/2} is x>=-3

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domain of f(x)=(sqrt(x+3)}{\frac{x+4)/2}

domain

f (x) = \frac{x + 3}{\frac{x + 4}{2}}

x \geq - 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

x \geq - 3

f (x) = \frac{1}{9 x + 6}

f (x) = \frac{x + 6}{( x - 2 ) ( x + 3 )}

f (x) = \frac{x ^{2} + 2}{x - 7}

f (x) = \frac{2 x + 2}{3 x + 10}

\frac{x ^{2} - 2 x + 6}{( x ^{2} + 2 ) ( x - 2 )}

What is the domain of f(x)=(sqrt(x+3)}{\frac{x+4)/2} ?
The domain of f(x)=(sqrt(x+3)}{\frac{x+4)/2} is x>=-3