What is the domain of f(x)=\sqrt[3]{5x^3+40} ?

The domain of f(x)=\sqrt[3]{5x^3+40} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{5x^3+40}

domain

f (x) = 3 5 x^{3} + 40

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1 x ^{2} + 4}{x + 6}

f (x) = \frac{1}{x} - 2

9 x + 6

\frac{( - x + ( 9 x ^{2} + 8 x ) )}{2 x}

2 (π) (r^{2}) + 12 (π) (r)

What is the domain of f(x)=\sqrt[3]{5x^3+40} ?
The domain of f(x)=\sqrt[3]{5x^3+40} is -infinity <x<infinity