What is the domain of f(x)= 1/(sqrt(6x^2-18x-60)) ?

The domain of f(x)= 1/(sqrt(6x^2-18x-60)) is x 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(sqrt(6x^2-18x-60))

domain

f (x) = \frac{1}{6 x ^{2} - 18 x - 60}

x < - 2 or x > 5

Interval Notation

(- \infty, - 2) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 5

Find undefined (singularity) points:

x = 5, x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > 5

f (x) = 3 x^{2} - 6 x

f (x) = 36 - x^{2} - x + 2

f (x) = \frac{x - 7}{x - 5}, x < 7

7 - 4 x

f (x) = lo g_{10} (\frac{1}{2}) (4 - ∣ x ∣)

What is the domain of f(x)= 1/(sqrt(6x^2-18x-60)) ?
The domain of f(x)= 1/(sqrt(6x^2-18x-60)) is x<-2\lor x>5