What is the domain of (4x+8)/(x^2+4x) ?

The domain of (4x+8)/(x^2+4x) is x 0

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domain of (4x+8)/(x^2+4x)

domain

\frac{4 x + 8}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

f (x) = \frac{( x + 2 )}{12 - x ^{2} - 25}

f (x) = 2 x - 1 (\frac{1}{2})

f (x) = \frac{2 x}{( 9 - x ^{2} ) ^{2}}

f (x) = (4 - 5 x^{3})^{- 2}

f (x) = \frac{9 x - 5}{x ^{2} - 9 x + 8}

What is the domain of (4x+8)/(x^2+4x) ?
The domain of (4x+8)/(x^2+4x) is x<-4\lor-4<x<0\lor x>0