What is the domain of f(x)=(x^2-4x)/(x^2-9) ?

The domain of f(x)=(x^2-4x)/(x^2-9) is x 3

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domain of f(x)=(x^2-4x)/(x^2-9)

domain

f (x) = \frac{x ^{2} - 4 x}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

\frac{x - 1}{x - 4}

f (x) = \frac{( x + 1 )}{( x + 1 ) \cdot ( 2 x - 3 )}

y = \frac{x}{x ^{2} + 2 x + 2}

x^{2} + 3 x - x

f (x) = 2 + x + 2

What is the domain of f(x)=(x^2-4x)/(x^2-9) ?
The domain of f(x)=(x^2-4x)/(x^2-9) is x<-3\lor-3<x<3\lor x>3