What is the domain of f(x)=((x+1))/((x+1)*(2x-3)) ?

The domain of f(x)=((x+1))/((x+1)*(2x-3)) is x 3/2

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domain of f(x)=((x+1))/((x+1)*(2x-3))

domain

f (x) = \frac{( x + 1 )}{( x + 1 ) \cdot ( 2 x - 3 )}

x < - 1 or - 1 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = \frac{3}{2}

The function domain

x < - 1 or - 1 < x < \frac{3}{2} or x > \frac{3}{2}

y = \frac{x}{x ^{2} + 2 x + 2}

x^{2} + 3 x - x

f (x) = 2 + x + 2

f (x) = lo g_{2} (x - 6)

f (x) = \frac{( x - 3 )}{( 2 x ^{2} + 10 x )}

What is the domain of f(x)=((x+1))/((x+1)*(2x-3)) ?
The domain of f(x)=((x+1))/((x+1)*(2x-3)) is x<-1\lor-1<x< 3/2 \lor x> 3/2