What is the domain of f(x)=sqrt(4-x^2)+sqrt(1+x) ?

The domain of f(x)=sqrt(4-x^2)+sqrt(1+x) is -1<= x<= 2

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domain of f(x)=sqrt(4-x^2)+sqrt(1+x)

domain

f (x) = 4 - x^{2} + 1 + x

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 2

V (x) = 8 x^{3} - 12 x^{2} + x - 9

f (x) = \frac{8}{x ^{2} - 7 x + 10}

f (x) = 1 - ln (x)

y = x x^{2} - 2

+ x - 2

What is the domain of f(x)=sqrt(4-x^2)+sqrt(1+x) ?
The domain of f(x)=sqrt(4-x^2)+sqrt(1+x) is -1<= x<= 2