What is the domain of f(x)=(sqrt(x-1))/(sqrt(4-x^2)) ?

The domain of f(x)=(sqrt(x-1))/(sqrt(4-x^2)) is 1<= x<2

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domain of f(x)=(sqrt(x-1))/(sqrt(4-x^2))

domain

f (x) = \frac{x - 1}{4 - x ^{2}}

1 \leq x < 2

Interval Notation

[1, 2)

Solution steps

Find non-negative values for radicals:

1 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

1 \leq x < 2

f (x) = - 0.002 x + 0.04

f (x) = \frac{x + 2}{9 - x}

\frac{1}{\frac{1}{x - 3}}

(\frac{1}{3})^{x - 2} + 4

y = \frac{4 - x ^{2}}{x ^{2} - x - 6}

What is the domain of f(x)=(sqrt(x-1))/(sqrt(4-x^2)) ?
The domain of f(x)=(sqrt(x-1))/(sqrt(4-x^2)) is 1<= x<2