What is the domain of f(x)=(x+7)/(x^2+3x)-4 ?

The domain of f(x)=(x+7)/(x^2+3x)-4 is x 0

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domain of f(x)=(x+7)/(x^2+3x)-4

domain

f (x) = \frac{x + 7}{x ^{2} + 3 x} - 4

x < - 3 or - 3 < x < 0 or x > 0

Interval Notation

(- \infty, - 3) \cup (- 3, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 3

The function domain

x < - 3 or - 3 < x < 0 or x > 0

f (x) = - \frac{1 x}{4} + \frac{9}{4}

+ (- 3) csc (2 π + x)

\frac{- 2 x + 4}{x ^{2} - 9}

f (x) = 5 x - 3 f (x) = \frac{9 x ^{2} - 4}{3 x + 2}

f (x) = x^{2} + 4 x - 12

What is the domain of f(x)=(x+7)/(x^2+3x)-4 ?
The domain of f(x)=(x+7)/(x^2+3x)-4 is x<-3\lor-3<x<0\lor x>0