What is the domain of sqrt((x+8)(x+2)) ?

The domain of sqrt((x+8)(x+2)) is x =-2

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domain of sqrt((x+8)(x+2))

domain

(x + 8) (x + 2)

x \leq - 8 or x \geq - 2

Interval Notation

(- \infty, - 8] \cup [- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 8 or x \geq - 2

The function domain

x \leq - 8 or x \geq - 2

f (x) = x^{2 - x^{2}}, 0 \leq x \leq 1

24 x^{2} - 15253 x + 591064

h (x) = \cdot f (x) = 5 - x \cdot (x^{2} - 1)

f (x) = \frac{1}{x ^{2} + 4 x - 60}

f (x) = \frac{e ^{x}}{1 + e ^{2 x}}

What is the domain of sqrt((x+8)(x+2)) ?
The domain of sqrt((x+8)(x+2)) is x<=-8\lor x>=-2