What is the domain of h(x)=*f(x)=sqrt(5-x)*(x^2-1) ?

The domain of h(x)=*f(x)=sqrt(5-x)*(x^2-1) is x<= 5

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domain of h(x)=f(x)=sqrt(5-x)(x^2-1)

domain

h (x) = \cdot f (x) = 5 - x \cdot (x^{2} - 1)

x \leq 5

Interval Notation

(- \infty, 5]

Solution steps

Find non-negative values for radicals:

x \leq 5

The function domain

x \leq 5

f (x) = \frac{1}{x ^{2} + 4 x - 60}

f (x) = \frac{e ^{x}}{1 + e ^{2 x}}

f (x) = 2 t - 3

\frac{x}{18 x ^{2} - 33 x - 40}

f (x) = x + 6 - 8

What is the domain of h(x)=*f(x)=sqrt(5-x)*(x^2-1) ?
The domain of h(x)=*f(x)=sqrt(5-x)*(x^2-1) is x<= 5