What is the domain of y= 1/(2xsqrt(3x-7)) ?

The domain of y= 1/(2xsqrt(3x-7)) is x> 7/3

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domain of y= 1/(2xsqrt(3x-7))

domain

y = \frac{1}{2 x 3 x - 7}

x > \frac{7}{3}

Interval Notation

(\frac{7}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{7}{3}

Find undefined (singularity) points:

x = \frac{7}{3}

Combine real regions and undefined points for final function domain

x > \frac{7}{3}

\frac{x - 4}{2}

f (x) = 3 x^{2} + 2 x - 5

\frac{2 x - 3}{1 - x ^{2}}

f (x) = x^{2} + 4 + 1

\frac{( x ^{2} - x )}{9 x}

What is the domain of y= 1/(2xsqrt(3x-7)) ?
The domain of y= 1/(2xsqrt(3x-7)) is x> 7/3