What is the domain of f(x)=sqrt(x^2+4)+1 ?

The domain of f(x)=sqrt(x^2+4)+1 is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+4)+1

domain

f (x) = x^{2} + 4 + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{( x ^{2} - x )}{9 x}

cot (θ)

f (x) = \frac{1}{20 - 8 x - x ^{2}}

f (x) = \frac{2 x - 1}{2 x ^{2} - 5 x - 6}

\frac{2 x ^{2}}{x + 1}

What is the domain of f(x)=sqrt(x^2+4)+1 ?
The domain of f(x)=sqrt(x^2+4)+1 is -infinity <x<infinity