What is the domain of f(x)=sqrt(2x^2+5) ?

The domain of f(x)=sqrt(2x^2+5) is -infinity <x<infinity

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domain of f(x)=sqrt(2x^2+5)

domain

f (x) = 2 x^{2} + 5

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = lo g_{3} (2 x - 1) - 2

y = - 4

y = \frac{x ^{2} + x - 6}{x - 2}

y = (x + 3) (x - 1) (x - 4)

- (x + 4)^{3} - 4

What is the domain of f(x)=sqrt(2x^2+5) ?
The domain of f(x)=sqrt(2x^2+5) is -infinity <x<infinity