What is the domain of f(x)=(sqrt(x)^2-3x-4)/(-x+5) ?

The domain of f(x)=(sqrt(x)^2-3x-4)/(-x+5) is 0 5

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domain of f(x)=(sqrt(x)^2-3x-4)/(-x+5)

domain

f (x) = \frac{x ^{2} - 3 x - 4}{- x + 5}

0 \leq x < 5 or x > 5

Interval Notation

[0, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

0 \leq x < 5 or x > 5

\frac{x}{x + 1}

y = \frac{1}{9 - x ^{2}}

f (x) = \frac{4}{3 - x}

- x^{2} + 1

f (x) = 1 - 7^{x}

What is the domain of f(x)=(sqrt(x)^2-3x-4)/(-x+5) ?
The domain of f(x)=(sqrt(x)^2-3x-4)/(-x+5) is 0<= x<5\lor x>5