What is the domain of y=(sqrt(3x-2-x^2))/(2x-4) ?

The domain of y=(sqrt(3x-2-x^2))/(2x-4) is 1<= x<2

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domain of y=(sqrt(3x-2-x^2))/(2x-4)

domain

y = \frac{3 x - 2 - x ^{2}}{2 x - 4}

1 \leq x < 2

Interval Notation

[1, 2)

Solution steps

Find non-negative values for radicals:

1 \leq x \leq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

1 \leq x < 2

f (x) = - 1 s i x = 0

f (x) = x^{2} sin (\frac{1}{x})

\frac{2 x - x ^{2}}{x ^{2} - 2 x + 1}

y = \frac{x ^{2}}{8 - x}

\frac{1}{( \frac{9}{x - 2} ) - 3}

What is the domain of y=(sqrt(3x-2-x^2))/(2x-4) ?
The domain of y=(sqrt(3x-2-x^2))/(2x-4) is 1<= x<2