What is the domain of f(x)=h(x)=sqrt(9+x) ?

The domain of f(x)=h(x)=sqrt(9+x) is x>=-9

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domain of f(x)=h(x)=sqrt(9+x)

domain

f (x) = h (x) = 9 + x

x \geq - 9

Interval Notation

[- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

The function domain

x \geq - 9

- x^{2} + 1

f (x, y) = ln (y - 6)

f (x) = \frac{2 x - 2}{- 2 x - x ^{2}}

e - 2 t

2 + 4 x - 7 x^{2}

What is the domain of f(x)=h(x)=sqrt(9+x) ?
The domain of f(x)=h(x)=sqrt(9+x) is x>=-9