What is the domain of-sqrt(x^2+1) ?

The domain of-sqrt(x^2+1) is -infinity <x<infinity

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domain of-sqrt(x^2+1)

domain

- x^{2} + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x, y) = ln (y - 6)

f (x) = \frac{2 x - 2}{- 2 x - x ^{2}}

e - 2 t

2 + 4 x - 7 x^{2}

f (x) = \frac{3 x - 6}{8 x ^{2} + 6 x - 5}

What is the domain of-sqrt(x^2+1) ?
The domain of-sqrt(x^2+1) is -infinity <x<infinity