What is the domain of f(x)=(sqrt(2x))/(7x-2) ?

The domain of f(x)=(sqrt(2x))/(7x-2) is 0 2/7

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domain of f(x)=(sqrt(2x))/(7x-2)

domain

f (x) = \frac{2 x}{7 x - 2}

0 \leq x < \frac{2}{7} or x > \frac{2}{7}

Interval Notation

[0, \frac{2}{7}) \cup (\frac{2}{7}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{2}{7}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{2}{7} or x > \frac{2}{7}

f (y) = - X + 3 + 1

f (x) = \frac{( x ^{4} )}{x ^{4} - 1}

f (x) = \frac{\frac{x}{x - 8}}{\frac{3}{x + 9}}

f (x) = \frac{13 x}{11 - 9 x - 22}

\frac{x + 6}{x - 2}

What is the domain of f(x)=(sqrt(2x))/(7x-2) ?
The domain of f(x)=(sqrt(2x))/(7x-2) is 0<= x< 2/7 \lor x> 2/7