What is the domain of f(x)=((x^4))/(x^4-1) ?

The domain of f(x)=((x^4))/(x^4-1) is x 1

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domain of f(x)=((x^4))/(x^4-1)

domain

f (x) = \frac{( x ^{4} )}{x ^{4} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{\frac{x}{x - 8}}{\frac{3}{x + 9}}

f (x) = \frac{13 x}{11 - 9 x - 22}

\frac{x + 6}{x - 2}

h (x) = 2 ln (6 - 2 x) + 2 x

f (x) = \frac{x - 3}{x - 4}

What is the domain of f(x)=((x^4))/(x^4-1) ?
The domain of f(x)=((x^4))/(x^4-1) is x<-1\lor-1<x<1\lor x>1