What is the domain of f(x)=2+1/(x^2) ?

The domain of f(x)=2+1/(x^2) is x 0

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domain of f(x)=2+1/(x^2)

domain

f (x) = 2 + \frac{1}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

y = lo g_{2} (6 x^{2} + 6 x - 36)

f (x) = \frac{5}{13 x + 2}

lo g_{6} (\frac{( w - 7 )}{( w + 3 )})

f (x) = arccos (\frac{x - 1}{2})

f (x) = \frac{( x - 3 )}{x ^{2} + 7 x + 6}

What is the domain of f(x)=2+1/(x^2) ?
The domain of f(x)=2+1/(x^2) is x<0\lor x>0