What is the domain of log_{6}(((w-7))/((w+3))) ?

The domain of log_{6}(((w-7))/((w+3))) is w 7

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domain of log_{6}(((w-7))/((w+3)))

domain

lo g_{6} (\frac{( w - 7 )}{( w + 3 )})

w < - 3 or w > 7

Interval Notation

(- \infty, - 3) \cup (7, \infty)

Solution steps

Find positive values for logs:

w < - 3 or w > 7

Find undefined (singularity) points:

w = - 3

Combine real regions and undefined points for final function domain

w < - 3 or w > 7

f (x) = arccos (\frac{x - 1}{2})

f (x) = \frac{( x - 3 )}{x ^{2} + 7 x + 6}

f (x) = lo g_{- 3} (x)

3 cos (4 x)

f (x) = x^{3} - 1 + x + 1

What is the domain of log_{6}(((w-7))/((w+3))) ?
The domain of log_{6}(((w-7))/((w+3))) is w<-3\lor w>7