What is the domain of f(x)=sqrt((2-x)/(x^2-1)) ?

The domain of f(x)=sqrt((2-x)/(x^2-1)) is x<-1\lor 1<x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((2-x)/(x^2-1))

domain

f (x) = \frac{2 - x}{x ^{2} - 1}

x < - 1 or 1 < x \leq 2

Interval Notation

(- \infty, - 1) \cup (1, 2]

Solution steps

Find non-negative values for radicals:

x < - 1 or 1 < x \leq 2

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or 1 < x \leq 2

f (x) = x^{6} + x + 10

f (x) = (\frac{3}{x})^{2}

f (x) = \frac{x - 7}{3}

\frac{6 x ^{2} - 9 x ^{2} + 1}{2 x - 3}

g (x) = \frac{2 x + 3}{3 x - 4}

What is the domain of f(x)=sqrt((2-x)/(x^2-1)) ?
The domain of f(x)=sqrt((2-x)/(x^2-1)) is x<-1\lor 1<x<= 2