What is the domain of h(x)= 2/(sqrt(x+2)) ?

The domain of h(x)= 2/(sqrt(x+2)) is x>-2

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domain of h(x)= 2/(sqrt(x+2))

domain

h (x) = \frac{2}{x + 2}

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

y = 9 x - 10

f (x) = \frac{x - 6}{- x + 9}

y = \frac{1}{x ( 3 - x ^{2} )}

f (x) = \frac{21 - 2 x}{x - 9}

6 - x^{2}

What is the domain of h(x)= 2/(sqrt(x+2)) ?
The domain of h(x)= 2/(sqrt(x+2)) is x>-2