What is the domain of f(x)=log_{x+1}(2x^2-5x+2) ?

The domain of f(x)=log_{x+1}(2x^2-5x+2) is -1 2

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domain of f(x)=log_{x+1}(2x^2-5x+2)

domain

f (x) = lo g_{x + 1} (2 x^{2} - 5 x + 2)

- 1 < x < 0 or 0 < x < \frac{1}{2} or x > 2

Interval Notation

(- 1, 0) \cup (0, \frac{1}{2}) \cup (2, \infty)

Solution steps

Check logs domain:

- 1 < x < 0 or 0 < x < \frac{1}{2} or x > 2

The function domain

- 1 < x < 0 or 0 < x < \frac{1}{2} or x > 2

y = x^{3} + x^{2} - 20 x

y = \frac{x ^{2} + 1}{x ^{2} - 1}

f (x) = 7 + 3 x

f (x) = \frac{3 x + 1}{2 x ^{2} - 7 x - 4}

f (x) = \frac{6}{x} x - 6

What is the domain of f(x)=log_{x+1}(2x^2-5x+2) ?
The domain of f(x)=log_{x+1}(2x^2-5x+2) is -1<x<0\lor 0<x< 1/2 \lor x>2