What is the domain of y=(x^2+1)/(x^2-1) ?

The domain of y=(x^2+1)/(x^2-1) is x 1

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domain of y=(x^2+1)/(x^2-1)

domain

y = \frac{x ^{2} + 1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 7 + 3 x

f (x) = \frac{3 x + 1}{2 x ^{2} - 7 x - 4}

f (x) = \frac{6}{x} x - 6

y = 1 - x

f (x) = \frac{( x + 1 ) ^{3}}{( x - 3 ) ^{2}}

What is the domain of y=(x^2+1)/(x^2-1) ?
The domain of y=(x^2+1)/(x^2-1) is x<-1\lor-1<x<1\lor x>1