What is the domain of y=(x^4+x^2+8)/(x^3-8x) ?

The domain of y=(x^4+x^2+8)/(x^3-8x) is x 2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(x^4+x^2+8)/(x^3-8x)

domain

y = \frac{x ^{4} + x ^{2} + 8}{x ^{3} - 8 x}

x < - 22 or - 22 < x < 0 or 0 < x < 22 or x > 22

Interval Notation

(- \infty, - 22) \cup (- 22, 0) \cup (0, 22) \cup (22, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 22, x = 22

The function domain

x < - 22 or - 22 < x < 0 or 0 < x < 22 or x > 22

f (x) = \frac{( x ^{2} )}{x ^{4} + 2}

f (x) = ln (13 x)

f (x) = \frac{\frac{1}{( x + 1 )}}{x ^{2} - 4}

f (x) = x^{3} - 2 x^{2}

x + 2 - 8

What is the domain of y=(x^4+x^2+8)/(x^3-8x) ?
The domain of y=(x^4+x^2+8)/(x^3-8x) is x<-2sqrt(2)\lor-2sqrt(2)<x<0\lor 0<x<2sqrt(2)\lor x>2sqrt(2)