What is the domain of (y/(y-2))^{1/3} ?

The domain of (y/(y-2))^{1/3} is y 2

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domain of (y/(y-2))^{1/3}

domain

(\frac{y}{y - 2})^{\frac{1}{3}}

y < 2 or y > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

y = 2

The function domain

y < 2 or y > 2

f (x) = 25 x^{2} + 40 x + 16

\frac{4 x}{x ^{2} - 9}

e^{5 x + 3} + 2

f (x) = \frac{3}{x + 1 - 2}

f (x) = (e^{\frac{1}{x}})^{3}

What is the domain of (y/(y-2))^{1/3} ?
The domain of (y/(y-2))^{1/3} is y<2\lor y>2